The current that flows when the capacitor is discharged. The current does not drop to zero immediately, but reaches zero after a certain time.

Initial current

\( I_0 \) Unit \( \mathrm{A} \)

The current at time \( t = 0 \). Its value is given by the applied source voltage \(U_0\) and the resistance \(R\): \( I_0 ~=~ \frac{U_0}{R}\).

Capacitance

\( C \) Unit \( \mathrm{F} \)

Electrical capacitance is a characteristic quantity of the capacitor and tells how many charges must be brought onto the capacitor to charge the capacitor to the voltage \( 1 \, \mathrm{V} \). The capacitance has an effect on how fast the capacitor can discharge.

Resistance

\( R \) Unit \( \mathrm{\Omega} \)

Resistor with resistance \( R \) connected in series with the capacitor. The resistance has an effect on how fast the capacitor can discharge.

Time

\( t \) Unit \( \mathrm{s} \)

At the time \(t = 0\) of the discharge process, the current has the value: \( I(0) = - I_0\). With time, the discharge current decreases to zero.

You must have JavaScript enabled to use this form.

Give feedback

Hey! I am Alexander, the physicist and author here. It's important to me that you are satisfied when you come here to get your questions answered and problems solved. But since I don't have a crystal ball, I depend on your feedback. That way I can eliminate mistakes and improve this content so that other visitors can benefit from your feedback.

How satisfied are you?

Very nice!

If there is anything you would like to see improved, please send me a message below. I would be very happy if you support the project.

Hmm...

Would you mind telling me what you were missing? Or what you didn't like? I take every feedback to heart and will adapt and improve the content.

What's the trouble?

Do not be disappointed, I can certainly help you. Just send me a message what you actually wanted to find here or what you don't like. I really take your feedback seriously and will revise this content. If you are very disappointed, explain your concern in the feedback and leave your email and I will try to help you personally.