Formula 1. Maxwell Equation in Integral Form Electric field Electric charge
$$\oint_A \class{blue}{\boldsymbol{E}} ~\cdot~ \text{d}\boldsymbol{a} ~=~ \frac{\class{red}{Q}}{\varepsilon_0}$$
Electric field
$$ \class{blue}{\boldsymbol{E}} $$ Unit $$ \frac{\mathrm V}{\mathrm m} $$ This quantity is a vector field (it assigns a field vector to each point in space) and tells how large the electric force on a test charge would be if it were placed in a particular location.
Surface
$$ A $$ The (imaginary) surface over which the electric field \( \class{blue}{\boldsymbol{E}} \) is integrated. This can be, for example, a spherical surface or a cylindrical surface. For example, to calculate the \( \class{blue}{\boldsymbol{E}} \) field inside a charged sphere, this imaginary surface is placed inside the charged sphere.
Here \( \text{d}\boldsymbol{a} \) is a infinitesimal piece of the surface. By definition the direction of \(\text{d}\boldsymbol{a}\) is perpendicular on the surface.
Electric charge
$$ \class{red}{Q} $$ Unit $$ \mathrm{C} $$ This is the charge that is enclosed by the selected surface \( A \).
Vacuum Permittivity
$$ \varepsilon_0 $$ Unit $$ \frac{\mathrm{As}}{\mathrm{Vm}} $$ This quantity always occurs in electromagnetic phenomena and is a natural constant with the value \( \varepsilon_0 ~=~ 8.854 \,\cdot\, 10^{-12} \, \frac{\text{As}}{\text{Vm}} \).