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Illustration Distance Traveled in Free Fall from Zero Starting Height

Distance traveled in free fall from zero starting height
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EA particle is dropped from the starting height \( y = 0\) at the time \( t = 0\): \( y(0) = 0\). The distance traveled \(y(t)\) within time \(t\) is given by the following distance-time law:$$ y(t) ~=~ \frac{1}{2} \, g \, t^2 $$Here \(g = 9.8 \, \frac{\mathrm m}{\mathrm{s}^2} \) is the gravitational acceleration on Earth.